Equation 677 Database

Magma d0db89ba8f59…

magma d0db89ba8f59
Size
189
Isomorphism class hash
d0db89ba8f5965b9782e0a0b0d51711c61020845795e9726303ead5de73d1b85
Satisfies Equation 255
yes
Right-cancellative
yes
Idempotent
no
Fiber matrix
symmetric: yes · normal: yes · rank: 1 (nullity 188) what is this?
Submitted by
qawbecrdtey
Submitted at
2026-10-08 15:15:40
Display reorder
188,9,17,29,22,13,30,24,26,25,16,12,20,1,27,11,32,14,15,7,5,21,2,18,10,28,3,6,35,33,34,23,4,31,19,8,0,184,139,138,141,142,134,135,144,146,137,103,140,145,106,143,105,133,136,147,185,175,170,177,178,169,171,180,181,174,109,176,182,112,179,110,172,173,183,187,104,158,153,165,150,154,126,128,157,124,107,127,111,167,123,151,156,129,186,149,152,163,164,159,155,168,130,148,108,162,131,125,166,122,160,161,132,69,89,81,83,75,79,47,93,91,78,87,88,74,84,99,61,86,85,76,114,118,64,82,116,120,46,97,90,49,51,117,80,121,100,45,77,95,96,68,71,40,42,57,54,59,92,73,65,66,67,56,58,102,55,63,62,60,115,70,36,41,113,38,43,98,72,50,52,53,39,119,101,37,48,94,44 history
Raw table
canonical order · displayed order
Equational Theories
Finite Magma Explorer

Commentary

Order 189, glued along a design with a hole: A(37;26,2,0) on the hole, A(5;2,4,0) on every block of five (its points in the order listed), and a point off the hole squares to itself. Two distinct points not both in the hole multiply in their block; two points of the hole, in A(37;26,2,0): x*y = 26x + 2y mod 37, on the labels 0..36. It satisfies Equation 677 because the blocks and the hole do. The design: a (189, {5, 37*})-PBD, the hole 0..36 and blocks of five meeting it at most once, every pair not both in the hole in exactly one block. The point (x, r), x in Z/19, r in 0..7, is 37 + 19r + x. Blocks off the hole: the translates (x, r) -> (x + t, r) of {(0,0), (1,0), (7,0), (11,0), (0,7)} {(4,0), (9,0), (6,0), (0,1), (0,7)} {(0,1), (13,1), (15,1), (10,1), (0,5)} {(2,1), (14,1), (3,1), (0,3), (0,6)} {(0,2), (16,2), (17,2), (5,2), (0,6)} {(8,2), (18,2), (12,2), (0,0), (0,5)} {(0,3), (2,3), (14,3), (3,3), (0,4)} {(8,3), (18,3), (12,3), (0,2), (0,4)} {(0,4), (8,4), (18,4), (12,4), (0,0)} {(13,4), (15,4), (10,4), (0,3), (0,5)} {(0,5), (8,5), (18,5), (12,5), (0,2)} {(4,5), (9,5), (6,5), (0,2), (0,7)} {(0,6), (2,6), (14,6), (3,6), (0,1)} {(1,6), (7,6), (11,6), (0,1), (0,4)} {(0,7), (13,7), (15,7), (10,7), (0,3)} {(16,7), (17,7), (5,7), (0,0), (0,6)}. A hole point h has a functional f on F_2^3 (r read in binary) and a in (Z/19)^8; its blocks are {h} + {(a_r + t, r) : f.r = e}, listed h first and then by increasing r, for e = 0, 1 and every t. Hole point 0 has the first (f, a) below; each further (f, a) gives the next three hole points, with a, 7a, 11a, in that order: f = 4, a = (0,0,0,0,0,0,0,0); f = 7, a = (0,0,17,16,12,10,3,18); f = 7, a = (0,9,15,7,4,14,17,12); f = 4, a = (0,11,10,13,15,8,0,11); f = 5, a = (0,17,4,13,15,9,6,6); f = 2, a = (0,18,10,6,14,11,8,14); f = 1, a = (0,18,17,5,5,2,10,14); f = 1, a = (0,16,3,8,7,12,9,13); f = 7, a = (0,18,14,2,10,16,7,5); f = 6, a = (0,2,3,0,8,18,12,3); f = 4, a = (0,9,1,8,8,9,7,15); f = 3, a = (0,4,7,9,15,2,8,1); f = 2, a = (0,16,10,14,6,8,6,9). Equation 255: satisfied. Idempotent elements: 153.

last edited by qawbecrdtey at 2026-10-08 15:15:41 · history